Answer:
q⁷t²¹
Explanation:
To write it in the exponential form, we will use the following properties
[tex]\begin{gathered} (ab)^x_{}=a^x\cdot b^x \\ (a^x)^y=a^{x\cdot y} \end{gathered}[/tex]
Therefore, applying the first property, we get:
[tex](qt^3)^7=q^7\cdot(t^3)^7[/tex]
Then, we can apply the second property to get:
[tex](qt^3)^7=q^7\cdot t^{3\cdot7}=q^7t^{21}[/tex]
So, the answer is:
q⁷t²¹
