The point (x,y) on unit circle is
[tex](x,y)=(\cos \theta,\sin \theta)[/tex]We know y is "sin theta" and sin is "opposite" over "hypotenuse". Thus, we can draw a triangle
We see that "5" is opposite of theta and 7 is the hypotenuse.
To get x, we use the pythagorean theorem:
[tex]\begin{gathered} \text{leg}^2+\text{AnotherLeg}^2=\text{Hypotenuse}^2 \\ x^2+5^2=7^2^{} \\ x^2+25=49 \\ x^2=49-25 \\ x^2=24 \\ x=\sqrt[]{24} \\ x=2\sqrt[]{6} \end{gathered}[/tex]From unit circle formula, we know value of x is cos. Thus, we take the cosine ratio, adjacent over hypotenuse.
Adjacent is 2 Sqrt(6) and Hypotenuse is 7 Thus,
[tex]x=\frac{2\sqrt[]{6}}{7}[/tex]
