Ace Hardware sold 48 boxes of pens and Ace Hardware sold 240 batteries
Explanation:
Cost for batteries = $3
Cost of small boxes of pens = $5
Total sales = $960
let number of batteries = b
number of boxes of pens = p
Cost for batteries (number of batteries) + Cost of small boxes of pens (number of boxes of pens) = Total sales
[tex]\begin{gathered} 3(b)\text{ + 5(p) = 960} \\ 3b\text{ + 5p = 960 }\ldots.(1) \end{gathered}[/tex]
From the questions, customers bought 5 times as many batteries as boxes of pens
b = 5 times of p
[tex]b=5p\text{ }\ldots\text{ (2)}[/tex]
Using substitution method
From equation 2, b ihas been made the subject of formula.
susbtitute for b in equation (1):
[tex]\begin{gathered} 3(5p)\text{ + 5p = 960} \\ 15p\text{ + 5p = 960} \\ 20p\text{ = 960} \\ \\ \text{divide both sides by 20:} \\ \frac{20p}{20}\text{ = }\frac{960}{20} \\ p\text{ = 48} \end{gathered}[/tex]
substitute for p in equation (2):
[tex]\begin{gathered} b\text{ = 5(48)} \\ b\text{ = 240} \end{gathered}[/tex]
Hence, Ace Hardware sold 48 boxes of pens and Ace Hardware sold 240 batteries
