We know h(x) and g(x)
[tex]\begin{gathered} h(x)=4 \\ g(x)=x^2 \end{gathered}[/tex]
And also we know that f(x) is a one-to-one function, and f^-1 is its inverse.
We can use the properties of compound functions to reduce problems.
A.
[tex](g\circ h\circ f^{-1})(x)[/tex]
We can calculate
[tex]g\circ h[/tex]
But, we don't know the exact value of f^-1. So we cannot know if the equality is true.
Finally, the answer is letter A.
For the rest options we can calculate them using the properties of compound functions.
