Answer:
Options B and C
Step-by-step explanation:
Finding the roots of a quadratic equation:
Suppose that we have a quadratic equation in the following format:
ax² + bx + c = 0
The roots are given by:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]In this question:
x² + 3x + 5 = 0
So a = 1, b = 3, c = 5
The roots are:
[tex]x=\frac{-3\pm\sqrt[]{3^2-4\ast1\ast5}}{2}=\frac{-3\pm\sqrt[]{-11}}{2}[/tex]So
[tex]x=\frac{-3+\sqrt[]{-11}}{2},x=\frac{-3-\sqrt[]{-11}}{2}[/tex]Options B and C
