A concave lens has a focal length of 3.12 m. Solve for the magnification of the image on the film of a height 0.30 m, if the size of the image is 0.83 m

Respuesta :

Given:

The focal length of the lens, f=3.12 m

The height of the film, h=0.30 m

The height of the image, h_i=0.83 m

To find:

The magnification of the lens.

Explanation:

The magnification of a lens is given by,

[tex]m=\frac{h_i}{h}[/tex]

On substituting the known values,

[tex]\begin{gathered} m=\frac{0.83}{0.30} \\ =2.77\text{ } \end{gathered}[/tex]

Final answer:

The magnification of the lens is 2.77