To prepare 1.0x10^-2M NaOH from 0.1M NaOH stock solution, you have to take a volume of the stock solution and dilute it using 9 times that volume of water. We conclude it from the equation for dilutions:
[tex]\begin{gathered} V1C1=V2C2 \\ 0.1V1=0.01V2 \\ \frac{0.1}{0.01}V1=V2 \\ 10V1=V2 \\ V1=\frac{1}{10}V2 \end{gathered}[/tex]It means that to prepare the 1.0x10^-2 solution, dilute 1 mL (for instance) of stock solution in 9mL of water.
