(9)Suppose that the Towngas supply pressure is 8.5 kPa (gauge pressure) andthe total volume is 2.4 m enters a building from outside where thetemperature is 10 °C and passes into a building where the temperature is 35°C, if the pressure was reduced to 2 kPa. What would be the new volume ofthe gas?

Respuesta :

ANSWER

35.7 m³

EXPLANATION

By the ideal gases law,

[tex]PV=nRT[/tex]

If we have the same gas in both situations, the product nR is constant, thus for this problem,

[tex]\frac{P_{\text{out}}V_{\text{out}}}{T_{\text{out}}}=\frac{P_{in}V_{in}}{T_{in}}[/tex]

The given information is:

• Pout = 8500 Pa

,

• Pin = 2000 Pa

,

• Tout = 10 °C

,

• Tin = 35 °C

,

• Vout = 2.4 m³

,

• Vin =?

We have to solve the equation above for Vin,

[tex]V_{in}=\frac{T_{in}}{P_{in}}\cdot\frac{P_{\text{out}}V_{\text{out}}}{T_{\text{out}}}[/tex]

Replace the values,

[tex]V_{in}=\frac{35C}{2000Pa}\cdot\frac{8500Pa\cdot2.4m^3}{10C}=35.7m^3[/tex]

The new volume of the gas is 35.7 m³