ANSWER
35.7 m³
EXPLANATION
By the ideal gases law,
[tex]PV=nRT[/tex]If we have the same gas in both situations, the product nR is constant, thus for this problem,
[tex]\frac{P_{\text{out}}V_{\text{out}}}{T_{\text{out}}}=\frac{P_{in}V_{in}}{T_{in}}[/tex]The given information is:
• Pout = 8500 Pa
,• Pin = 2000 Pa
,• Tout = 10 °C
,• Tin = 35 °C
,• Vout = 2.4 m³
,• Vin =?
We have to solve the equation above for Vin,
[tex]V_{in}=\frac{T_{in}}{P_{in}}\cdot\frac{P_{\text{out}}V_{\text{out}}}{T_{\text{out}}}[/tex]Replace the values,
[tex]V_{in}=\frac{35C}{2000Pa}\cdot\frac{8500Pa\cdot2.4m^3}{10C}=35.7m^3[/tex]The new volume of the gas is 35.7 m³