Given data:
The given slope of the line is m=-1/3.
The given point is (a, b)=(0,2).
The given equation of the line in poin slope form is,
[tex]y-b=m(x-a)_{}[/tex]Substitute the given values in the above expression.
[tex]\begin{gathered} y-2=-\frac{1}{3}(x-0)_{} \\ 3y-6=-x \\ x+3y=6 \end{gathered}[/tex]Thus, the equation of the line is x+3y=6.
