Given the quadratic equation:
[tex]0.15t^2-44t+1200=0[/tex]Let's solve fot t.
Apply the standard quadratic equation:
[tex]\begin{gathered} ax^2+bx+c=0 \\ \\ 0.15t^2-44t+1200=0 \end{gathered}[/tex]Hence, we have the values:
• a = 0.15
,• b = -44
,• c = 1200
To solve for t apply the quadratic formula:
[tex]t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Thus, we have:
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