ANSWER
The volume will be one-half of the original volume
option A
EXPLANATION
Given that;
The initial moles of the gas is 2 moles
The final mole of the gas is 1 mole
The mathematical representation of the Avogadro's law is given below as
[tex]\frac{\text{ V}_1}{\text{ n}_1}\text{ = }\frac{\text{ V}_2}{\text{ n}_2}[/tex]
Let n1 = 2 moles and n2 = 1 mole
[tex]\begin{gathered} \text{ }\frac{\text{ V}_1}{\text{ 2}}\text{ = }\frac{\text{ V}_2}{\text{ 1}} \\ \text{ cross multiply} \\ \text{ V}_2\text{ }\times\text{ 2 = V}_1\text{ }\times\text{ 1} \\ \text{ Divide both sides by 2} \\ \text{ V}_2\text{ = }\frac{\text{ V}_{1\text{ }}}{\text{ 2}} \\ \frac{}{} \\ \text{ V}_2\text{ = }\frac{\text{ 1}}{\text{ 2}}V_1 \end{gathered}[/tex]
Therefore, the volume will be one-half of the original volume
option A
