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If it takes a bus 5.88 seconds to go from 5 m/s to 15 m/s what is its rates of acceleration?A) 2.55 m/s ^2B) 1.70 m/s C) 1.70 m/s ^2 D) 0.85 m/s ^2

Respuesta :

Given

Time taken, t=5.88 sec

Initial velocity, u=5 m/s

Final velocity, v=15 m/s

To find

The rate of acceleration

Explanation

Let the acceleration be a.

By equation of kinematics

[tex]\begin{gathered} v=u+at \\ \Rightarrow15=5+5.88a \\ \Rightarrow a=\frac{10}{5.88}=1.70\text{ m/s}^2 \end{gathered}[/tex]

Conclusion

The acceleration is

B.

[tex]1.70\text{ m/s}^2[/tex]

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