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you are asked to draw a colored marble out of there are 6 red marbles 3 blue marbles and 6 green marbles in the Box what is the probability of drawing a red marble and then a green marble without replacing the first marble round to the three decimal places

Respuesta :

Given:

there are 6 red marbles 3 blue marbles and 6 green marbles in the Box

So, the total marbles = 6 + 3 + 6 = 15

The probability of drawing a red marble = 6/15

After drawing the red, the remaining marbles = 14

The probability of drawing a green marble = 6/14

So, the probability of drawing a red marble and then a green marble without replacing the first marble =

[tex]\frac{6}{15}\cdot\frac{6}{14}=\frac{6}{35}=0.171[/tex]

So, the answer will be 0.171

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