Respuesta :
Given:
• Mass of each, m = 1.67 x 10⁻²⁷ kg
,• Velocity, v = 9.26 x 10⁶ m/s
,• B = 2.84 teslas
Let's sole for the following:
• (a). What magnetic force acts on the alpha particle?
Apply the formula:
[tex]F=qvB[/tex]Where:
Charge of proton = 1.609 x 10⁻¹⁹ C
Charge of neutron = 0
Thus, we have:
[tex]\begin{gathered} F=(2*1.609\times10^{-19})*(9.26\times10^6)*2.84 \\ \\ F=8.46\times10^{-12}\text{ N} \end{gathered}[/tex]The magnetic force that acts on the alpha particle is 8.46 x 10⁻¹² N.
• (b). Let's find the radius of curvature of the path of the alpha particle?
To find the radius, apply the formula:
[tex]F=\frac{mv^2}{r}[/tex]Where:
F is the force
m is the total mass
v is the velocity
r is the radius
Rewrite the formula for r, plug in the values and solve.
We have:
[tex]\begin{gathered} r=\frac{mv^2}{F} \\ \\ r=\frac{(4*1.67\times10^{-27})*(9.26\times10^6)^2}{8.46\times10^{-12}} \\ \\ r=\frac{5.7279\times10^{-13}}{8.46\times10^{-12}} \\ \\ r=0.0677 \\ \\ r=6.77\times10^{-2}\text{ m} \end{gathered}[/tex]The radius of the curvature of the path is 6.77 x 10⁻² m.
ANSWER:
(a). 8.46 x 10⁻¹² N.
(b). 6.77 x 10⁻² m.
