Given:
The dimension of the given paper is,
[tex]\begin{gathered} l=8.5in \\ b=11in \end{gathered}[/tex]
To find:
The dimension of the square paper and the length of the diagonal after folding the paper to the smallest side and trimming it.
Explanation:
If we fold the given paper to the lower opposite side and trim off the excess paper, then new dimensions would be,
[tex]\begin{gathered} l=8.5in \\ b=8.5in \end{gathered}[/tex]
Which is a square of side a = 8.5 inches. Because all sides are equal.
Using the length of the diagonal formula,
[tex]\begin{gathered} l=\sqrt{2}a \\ l=\sqrt{2}\times8.5 \\ l=8.5\sqrt{2}in \end{gathered}[/tex]
Final answer:
The dimensions of the square paper are,
[tex]a=8.5in[/tex]
The length of the diagonal is,
[tex]l=8.5\sqrt{2}in[/tex]
