(-3,0)
1) Let's solve that system, using this method. We need to pick one variable first.
-4x+5y=12
2x+5y=-6
2) Let's eliminate x, multiplying the 2nd equation by 2
-4x+5y=12
4x+10y=-12 Adding both equations simultaneously
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15y =0
y= 0
3) Plug y=0 into one of those equations, usually the simplest.
2x+5y=-6
2x+5(0)=-6
2x = -6 Dividing both sides by 2
x= -3
Hence, the answer is (-3,0)
