Given the following question:
[tex]\begin{gathered} 3x+2y=-12 \\ x=4y-18 \end{gathered}[/tex][tex]\begin{gathered} 3x+2y=-12 \\ x=4y-18 \\ \text{ Substitute x=4y - 18 into the first equation:} \\ 3(4y-18)+2y=-12 \\ 18-4=14y \\ 14y-54=-12 \\ -12+54=42 \\ y=3 \\ \text{ Substitute to find x} \\ x=4\times3-18 \\ 4\times3=12 \\ 12-18=-6 \\ x=-6,y=3 \\ x=-6 \end{gathered}[/tex]
Option B is your answer.
