Write the simplest polynomial function with integral coefficients that had the given zeros. 7,-7i

To find to polynomial from zeros.
Find the factors. If it is a positive zero, the factor will be (x- zero) If it is a negative zero if is (x+zero)
Multiply the factors together.
Zeros of 7, -7i would be:
Find the factors:
[tex](x-7)(x\pm7i)[/tex]Multiply the factors together: Will start out with FOIL for (x-7)(x+-7i) =
[tex]\begin{gathered} (x-7)(x\pm7i) \\ (x-7)(x+7i)(x-7i) \\ (x-7)(x^2-7ix+7ix-49i^2) \end{gathered}[/tex]Combine like terms. Then multiply by the last factor
[tex]\begin{gathered} x-7(x^2-49(-1)) \\ \text{where i}^2=-1 \\ (x-7)(x^2+49) \\ x^3+49x-7x^2-343 \\ x^3-7x^2+49x-343 \end{gathered}[/tex]Therefore the correct answer from the Option is D