Given:
Ths length of the rectangle B is, l = 8 cm.
The breadth of the rectnagle is, b = 1 cm.
The objective is to find the Perimeter and Area of the rectangle B.
The perimeter of the rectangle B can be calculated as,
[tex]\begin{gathered} P=2(l+b) \\ =2(8+1) \\ =2(9) \\ =18\text{ cm} \end{gathered}[/tex]The area of the rectangle B can be calculated as,
[tex]\begin{gathered} A=l\times b \\ =8\times1 \\ =8cm^2 \end{gathered}[/tex]Hence, the perimeter of the reaaaaacngle is, 18 cm and the area of the rectangle is 8 square centimeters.
