Step 1
Given;
Step 2
1) The equation of the line in slope-intercept form will be;
[tex]\begin{gathered} y=mx+b \\ m=\frac{y_2-y_1}{x_2-x_1}=\frac{6-5}{5-3}=\frac{1}{2} \end{gathered}[/tex][tex]\begin{gathered} y=5 \\ x=3 \\ 5=\frac{1}{2}(3)+b \\ 10=3+2b \\ 10-3=2b \\ b=\frac{7}{2} \\ b=3.5 \end{gathered}[/tex]
Thus the equation will be;
[tex]y=\frac{1}{2}x+3.5[/tex]
Answer;
[tex]y=\frac{1}{2}x+3.5[/tex]
