Solve for X in the following triangle using cosine law. Show your work

Given:
Required:
We need to find the value of X by using cosine law
Explanation:
First the formula to find angle by cosine law is
[tex]X=\cos^{-1}(\frac{c^2+b^2-a^2}{2cb})[/tex]where
a is the length of BC
b is the length of AC
c is the length of AB
X is the opposite angle of a
now put all the values
[tex]X=\cos^{-1}(\frac{110^2+100^2-70^2}{2*110*100})=38.57\degree[/tex]Final answer:
value of X is 38.57 degree