Need help with this one 3 tutors have canceled I been on it for 30 min

Answer: We have to find the JK, the simple answer is as follows, it is calculated by first finding the angle M and then using a trigonometric ratio to calculate the JK.
The simple and brief steps are as follows:
[tex]\begin{gathered} \angle M=\theta_T=\sin^{-1}(\frac{LJ}{LM})=\sin^{-1}(\frac{12}{20})=36.869897646^{\circ} \\ \\ \theta=\frac{\theta_T}{2}=18.434948823^{\circ}\approx18.435^{\circ} \end{gathered}[/tex]Therefore the JK is:
[tex]\begin{gathered} \tan(\theta)=\frac{JK}{JM}\rightarrow\tan(18.435^{\circ})=\frac{JK}{16} \\ \\ \\ JK=16\tan(18.435^{\circ})=5.3333333\approx5.34 \\ \\ \\ JK\approx5.34 \end{gathered}[/tex]Therefore JK is 5.34.