Given
A m=3.5 kg artillery shell is shot out of a cannon at v=375 m/s. It plunges into enemy bunker to s=1.3 m.
To find
The force
Explanation
Let the force be F.
By work-energy theorem,
Work done is equivalent to the energy.
Thus,
[tex]\begin{gathered} \frac{1}{2}mv^2=F\times s \\ \Rightarrow\frac{1}{2}3.5\times375^2=1.3F \\ \Rightarrow F=1.8\times10^5N \end{gathered}[/tex]Conclusion
The force that the shell exerts is
[tex]1.8\times10^5N[/tex]