In order to find the correct system, let's find the equation of each line.
To do so, first let's find the slope of each line with the formula below:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1}\\ \\ \\ \\ m_1=\frac{9-6}{4-0}=\frac{3}{4}\\ \\ \\ \\ m_2=\frac{3-6}{2-3}=\frac{-3}{-1}=3 \end{gathered}[/tex]Now, let's use the point-slope formula and then rewrite in the standard form:
[tex]\begin{gathered} (y-y_1)=m(x-x_1)\\ \\ \\ \\ point\text{ \lparen0,6\rparen }and\text{ m=3/4}\\ \\ (y-6)=\frac{3}{4}(x-0)\\ \\ y-6=\frac{3}{4}x\\ \\ 4y-24=3x\\ \\ 3x-4y=-24\\ \\ \\ \\ point\text{ \lparen3,6\rparen }and\text{ m=3}\\ \\ (y-6)=3(x-3)\\ \\ y-6=3x-9\\ \\ 3x-y=3 \end{gathered}[/tex]The equations are 3x - 4y = -24 and 3x - y = 3, therefore the correct system is the fourth one.
