A current of 1.2 A flows through a light bulb when it is connected across a 120 V source. What power is dissipated by the bulb?

Answer:
144 Watts
Explanation:
The power dissipated is equal to
P = IV
Where I is the current and V is the voltage. Replacing I = 1.2 A and V = 120 V, we get
P = (1.2A)(120 V)
P = 144 Watts
Therefore, the power is 144 Watts