First, since the triangle HKJ is isosceles, then it is true that
Therefore, in the exercise KHJ it is equal to the angle HKJ. We know that the sum of the internal angles of a triangle is 180, so we have
[tex]\begin{gathered} 180-70=110 \\ \end{gathered}[/tex]We divide by 2 to find the measure of the two equal sides of the triangle HKJ
[tex]\frac{110}{2}=55[/tex]Then, the angle HKJ measure 55. So,
[tex]\begin{gathered} \text{GKH}=180-(28+55+70) \\ \text{GKH}=180-153 \\ \text{GKH}=27 \end{gathered}[/tex]
