Given
Weight of the object, W=1200 N
Distance travelled , s=5.0 m
Input energy, Q=8000J
To find
The efficiency of the engine
Explanation
The efficiency is the ratio of work done to the input energy
So
[tex]\begin{gathered} \eta=\frac{W.s}{Q} \\ \Rightarrow\eta=1200\times\frac{5}{8000} \\ \Rightarrow\eta=0.75 \end{gathered}[/tex]Conclusion
The efficiency is 0.75
