Given
380 miles per hour
2562 miles with the wind
1998 miles against
Procedure
v = speed
v = 380 miles per hour
w = wind
v1 = v + w
v2 = v - w
t = same length of time
[tex]\begin{gathered} x_1=v_1t \\ x_2=v_2t \\ \\ \frac{x_1}{v_1}=\frac{x_2}{v_2} \\ \\ x_1(v_2)=x_2v_1 \\ x_1v_2-x_2v_1=0 \\ 2562(380-w)-1998(380+w)=0 \\ 973560-2562w-759240-1998w=0 \\ 214320-4560w=0 \\ w=\frac{214320}{4560} \\ w=47 \end{gathered}[/tex]The answer would be w = 47 miles per hour
