I need to know how to do this step by step. I'm having trouble with figuring out what comes first and What do I have to do next when solving the problem

The given inequality is
[tex]3y\leq2y+3[/tex]First, we need to isolate y
To do that we want to move 2y from the right side to the left side, then
To do that subtract 2y from 3y and subtract 2y from (2y + 3)
[tex]3y-2y\leq2y-2y+3[/tex]Since 3y - 2y = 1y
Since 2y - 2y = 0
[tex]\begin{gathered} 3y-2y\leq(2y-2y)+3 \\ 1y\leq0+3 \end{gathered}[/tex]Since 0 + 3 = 3
Then the answer is
[tex]\begin{gathered} 1y\leq3 \\ y\leq3 \end{gathered}[/tex]The answer is B