To find:
The value of given expression at x = 1 and y = 2.
[tex](3x\times x)^2-(\frac{x}{y})^{-2}[/tex]
Solution:
It is known that
[tex]a^{-b}=(\frac{1}{a})^b[/tex]
Substitute x = 1 and y = 2, in the expression and simplify as follows:
[tex]\begin{gathered} (3x\times x)^2-(\frac{x}{y})^{-2}=(3(1)\times1)^2-(\frac{1}{2})^{-2} \\ =(3)^2-(2)^2 \\ =9-4 \\ =5 \end{gathered}[/tex]
Thus, the answer is 5.
