A group has at most 200 spend on tood Sandwiches cost 15 and drinks cost $3.
Let the number of tood sandwich be x and the number of drinks be y.
Each tood sandwich costs $15.
Therefore, x tood sandwich cost 15x.
Each drink costs $3.
Therefore, y drinks cost 3y.
Group has at most $200.
Then,
[tex]15x+3y\leq200[/tex]Hence, the inequality describing the sitiation is
[tex]15x+3y\leq200[/tex]