The daily cases parabola peaks at T:
[tex]T=\frac{1}{r}\ln \frac{N_{\infty}-N_0}{N_0}[/tex]
r in the first page is:
[tex]r=\frac{\ln 2}{3}[/tex]
Given data:
[tex]\begin{gathered} N_{\infty}=3.3M \\ N_0=10 \end{gathered}[/tex]
Calculate T with the given data.
[tex]\begin{gathered} T=\frac{1}{\frac{\ln2}{3}}\ln \frac{3.3M-10}{10} \\ \\ T=\frac{3}{\ln2}\ln \frac{3299990}{10} \\ \\ T=\frac{3}{\ln2}\ln 329999 \\ \\ T\approx55 \end{gathered}[/tex]
Then, the daily cases peak is at T=55 (approximately)
