We have to find the price of one loaf of bread.
With the information we have, we can construct a system of equations.
Let B be the price of one loaf of bread and R the price of a roll.
Then, if one loaf of bread and six rolls cost $1.80, we can write:
[tex]B+6R=1.80[/tex]We also know that two loaves of bread and four rolls cost $2.40, so we can write:
[tex]2B+4R=2.40[/tex]We can solve for B with the method of elimination: we can substract the first equation from 1.5 times the second equation.
This can be express in mathematica terms as:
[tex]\begin{gathered} 1.5(2B+4R)-(B+6R)=1.5\cdot2.40-1.80 \\ 3B+6R-B-6R=3.60-1.80 \\ (3-1)B+(6-6)R=1.80 \\ 2B=1.80 \\ B=\frac{1.80}{2} \\ B=0.90 \end{gathered}[/tex]Then, we have just calculated that the loaf of bread costs $0.90.
Answer: the cost of a loaf of bread is $0.90.