We can find the number that is between 3/16 and 1 7/8 by averaging both numbers.
This is: sum the two numbers and then divide by two:
[tex]\begin{gathered} \frac{1}{2}\lbrack\frac{3}{16}+(1+\frac{7}{8})\rbrack \\ \frac{1}{2}\lbrack\frac{3}{16}+\frac{8+7}{8}\rbrack \\ \frac{1}{2}(\frac{3}{16}+\frac{15}{8}) \\ \frac{1}{2}(\frac{3}{16}+\frac{30}{16}) \\ \frac{1}{2}(\frac{33}{16}) \\ \frac{33}{32} \\ \frac{32+1}{32} \\ \frac{32}{32}+\frac{1}{32} \\ 1+\frac{1}{32} \end{gathered}[/tex]
Answer: 1 1/32 (option C)
