We have a system of equations:
[tex]\begin{gathered} A+C=200 \\ 8A+4C=1304 \end{gathered}[/tex]We can solve this by substitution, using the first equation:
[tex]C=200-A[/tex]Then, we replace this in the second equation:
[tex]\begin{gathered} 8A+4(200-A)=1304 \\ 8A+800-4A=1304 \\ 4A=1304-800 \\ 4A=504 \\ A=\frac{504}{4}=126 \end{gathered}[/tex]Now we can calculate C as:
[tex]C=200-A=200-126=74[/tex]Answer:
Adult tickets (A) = 126
Children tickets (C) = 74