Given:
The volume of wood is
[tex]V=2.10\times10^{-4}\text{ m}^3[/tex]
The density of wood is
[tex]\rho_w=3.73\times10^2\text{ kg/m}^3[/tex]
The volume of iron is
[tex]V=2.10\times10^{-4}\text{ m}^3[/tex]
The density of iron is
[tex]\rho_{iron}=\text{ 7.86}\times10^3\text{ kg/m}^3[/tex]
The density of water is
[tex]\rho_{water}=\text{ 997 kg/m}^3[/tex]
To find the buoyant force on wood and on iron.
Explanation:
The buoyant force can be calculated by the formula
[tex]B=V\times\rho_{water}\times g[/tex]
Here, g =9.8 m/s^2 is the acceleration due to gravity.
On substituting the values, the buoyant force on the wood is
[tex]\begin{gathered} B_{wood}=2.10\times10^{-4}\times997\times9.8 \\ =\text{ 2.052 N} \end{gathered}[/tex]
On substituting the values, the buoyant force on the iron is
[tex]\begin{gathered} B_{iron}=2.10\cdot10^{-4}\times997\times9.8 \\ =2.052\text{ N} \end{gathered}[/tex]
