To calculate the area of this figure, we need to divide it in 3 different figures:
For the second rectangle, we have a base of:
[tex]\begin{gathered} \text{base}=5+3=8\text{ km} \\ \text{height}=14\operatorname{km} \\ \text{Then, its area would be:} \\ A=8\cdot14 \\ A=112m^2 \end{gathered}[/tex]
Then, for the triangle:
[tex]\begin{gathered} A_{triangle}=\frac{\text{base}\cdot\text{height}}{2} \\ A_{triangle}=\frac{5\cdot4}{2}=\frac{20}{2}=10m^2 \end{gathered}[/tex]
Now, since we have the area of all the figures inside, we can add up all of them and get the total area:
[tex]\begin{gathered} A_{total}=24+112+10 \\ A_{total}=146m^2 \end{gathered}[/tex]
