SOLUTION
(a)
f(g(0)) From the table
[tex]\begin{gathered} g(0),\text{ that is the value of g\lparen x\rparen when x = 0 is 6} \\ put\text{ into f\lparen x\rparen, f\lparen6\rparen, that is value of f\lparen x\rparen when x = 6 is 2} \end{gathered}[/tex]
Hence f(g(0)) = 2
(b)
g(f(9)) from the table
[tex]\begin{gathered} f(9)=8 \\ g(8)=1,\text{ } \\ \end{gathered}[/tex]
Hence g(f(9)) = 1
(c)
f(f(1))
[tex]\begin{gathered} f(1)=7 \\ f(7)=5 \end{gathered}[/tex]
hence f(f(1)) = 5
(d)
g(g(2))
[tex]\begin{gathered} g(2)=4 \\ g(4)=2 \end{gathered}[/tex]
Hence g(g(2)) = 2
