What is the weight of the piece of aluminum shown below at 0.0974 lbs/in.^3 (hint:subtract the volume of the cylindrical hole.) Round to the nearest tenth as needed.

What is the weight of the piece of aluminum shown below at 00974 lbsin3 hintsubtract the volume of the cylindrical hole Round to the nearest tenth as needed class=

Respuesta :

We will have the following:

First, we will determine the volume of the side plate:

[tex]V_1=0.5\cdot4\cdot5\Rightarrow V_1=10[/tex]

Now, we find the volume of the front plate:

[tex]V_2=0.5\cdot4\cdot4-\pi(2)^2(0.5)\Rightarrow V_2=8-2\pi[/tex]

Now, we calculate the total volume:

[tex]V_t=2V_1+V_2\Rightarrow V_t=2(10)+(8-2\pi)[/tex][tex]\Rightarrow V_t=28-2\pi[/tex]

Now, we calculate its weight:

[tex]w=0.0974\cdot\frac{b}{in^3}\cdot(28-2\pi)\cdot in^3\Rightarrow w=2.115217751\ldots[/tex][tex]\Rightarrow w\approx2.1[/tex]

So, it's weight is approximately 2.1 Lb.