The equation of a circle located at a distance (a,b) from the origin is given by
[tex]y=(x-a)^2+(y-b)^2=r^2[/tex]Given:
[tex]\begin{gathered} y=(x-6)^2\text{ + (}y-2)^2\text{ = 81} \\ y=(x-6)^2\text{ + (}y-2)^2\text{ = }9^2 \end{gathered}[/tex]To get the coordinates, we will have to compare the given equation to the equation of the
circle
Upon comparing the terms and coefficient,
a = 6
b= 2
r = 9
Hence the center of the circle is (6,2)
radius = 9
