It is given that the two cyclists started at the same point and traveled in opposite directions for 4 hours, at a distance of 156 meters apart.
It is also given that one cyclist travels 9 mi/h slower than the other.
It is required to find the speed or rate of each cyclist in mi/h.
Recall the formula for distance, d:
[tex]d=s\cdot t[/tex]Where s is the rate in mi/h and t is the time spent in hours.
Let the rate of the faster cyclist be x mi/h, it follows that the rate of the cyclist who is
9 mi/h slower is (x-9) mi/h.
Find the distance covered by the faster cyclist by substituting s=x and t=4 into the distance formula:
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