Given that C(x) is a linear function, it can be expressed as:
[tex]C(x)=a+bx,[/tex]where a, and b are constants.
Now, we are given that there is a fixed cost of 100, therefore, a=100. Now, we know that
[tex]C(30)=1000.[/tex]Therefore:
[tex]1000=100+b(30).[/tex]Solving the above equation for b, we get:
[tex]\begin{gathered} 1000-100=30b, \\ 900=30b, \\ b=\frac{900}{30}, \\ b=30. \end{gathered}[/tex]