What is the probability that a randomly selected student will earn a 91 - 100 given they study for two to three hours?

Explanation
Let the probability that those who earn 91-100 be Pr(A) and the probability that those who studied for 2-3 hours be Pr(B)
[tex]Pr(A|B)=\frac{Pr(A\cap B)}{Pr(B)}=\frac{22}{45}[/tex]Answer: 22/45 or 49.9%