Recall that the equation of a line in slope-intercept form is as follows:
[tex]y=mx+b,[/tex]
where m is the slope of the line and (0,b) is its y-intercept.
Adding 5y-25 to the given equation we get:
[tex]\begin{gathered} 17x-5y+5y-25=25+5y-25, \\ 17x-25=5y. \end{gathered}[/tex]
Dividing the above equation by 5 we get:
[tex]\begin{gathered} \frac{17x-25}{5}=\frac{5y}{5}, \\ \frac{17}{5}x-5=y. \end{gathered}[/tex]
Then:
[tex]y=\frac{17}{5}x+(-5).[/tex]
Therefore the slope of the given line is 17/5 and its y-intercept is (0,-5).
Answer:
[tex]\begin{gathered} Slope:\frac{17}{5}, \\ y-intercept:(0,-5). \end{gathered}[/tex]
