Part A:
The parachutist's speed is 55 m/s.
This means he covers 55m distance in every second
To convert this 55m distance to feet,
[tex]\begin{gathered} 1m=3.3ft \\ 55m=55\times3.3 \\ =181.5ft \end{gathered}[/tex]The speed will be a distance of 181 feet covered every second.
Hence, the speed in feet per second is;
[tex]181.5ft\text{ per second}[/tex]Part B:
The distance covered by the parachutist during 15 seconds of free fall will be;
Given:
[tex]\begin{gathered} \text{speed, s = 181.5 ft per second} \\ t=15\text{seconds} \\ distance,d=\text{?} \\ \text{speed = }\frac{dis\tan ce}{\text{time}} \\ \text{distance = spe}ed\text{ }\times time \\ d=181.5\times15 \\ d=2722.5ft \end{gathered}[/tex]Therefore, the parachutist fell 2722.5 feet in 15seconds during free fall.
