[tex]\begin{gathered} \text{Given angle 30}^o, \\ \text{the hypotenuse is b} \\ \text{the opposite is a} \\ the\text{ adjacent is 12} \end{gathered}[/tex][tex]\begin{gathered} \text{from SOH CAH TOA} \\ \tan \theta=\frac{opposite}{adjacent} \\ \tan 30=\frac{a}{12} \\ a=12\tan 30 \\ a=12(\frac{1}{\sqrt[]{3}}) \\ a=\frac{12}{\sqrt[]{3}} \end{gathered}[/tex][tex]\begin{gathered} \cos \theta=\frac{adjacent}{hypotenuse} \\ \cos 30=\frac{12}{b} \\ b=\frac{12}{\cos 30} \\ b=\frac{12\times2}{\sqrt[]{3}} \\ b=\frac{24}{\sqrt[]{3}} \end{gathered}[/tex]
