I need help with this practice I attempted this practice previously and my attempt is in the picture

We will draw a sketch for the given triangle to find its area
The area of the triangle will be
[tex]A=\frac{1}{2}\times XY\times ZM[/tex]Since ZX = ZY = 7, then the triangle is isosceles
Then the height ZM will bisect the base XY
Then we can find ZM by using Pythagoras Theorem
[tex]\begin{gathered} ZM=\sqrt[]{7^2-3^2} \\ ZM=\sqrt[]{49-9} \\ ZM=\sqrt[]{40} \\ ZM=2\sqrt[]{10} \end{gathered}[/tex]Since XY = 6, then
The area of the triangle is
[tex]\begin{gathered} A=\frac{1}{2}\times6\times2\sqrt[]{10} \\ A=6\sqrt[]{10}\text{ square units} \end{gathered}[/tex]