The acceleration of the car can be given as,
[tex]a=\frac{F}{m}[/tex]Plug in the known values,
[tex]\begin{gathered} a=\frac{3000\text{ N}}{1000\text{ kg}}(\frac{1kgm/s^2}{1\text{ N}})_{} \\ =3m/s^2 \end{gathered}[/tex]The net force which acts on the car is,
[tex]F=ma[/tex]The frictional force acting on the car is,
[tex]f=\mu_kmg[/tex]The net force is balanced by the frictional force which can be solved as,
[tex]\begin{gathered} \mu_kmg=ma \\ \mu_k=\frac{a}{g} \end{gathered}[/tex]Substitute the known values,
[tex]\begin{gathered} \mu_k=\frac{3m/s^2}{9.8m/s^2} \\ =0.306 \end{gathered}[/tex]Thus, the coefficient of kinetic friction is 0.306.
