Given
[tex](e^{2-\sqrt{3}})^{2+\sqrt{3}}[/tex]
To simplify.
Explanation:
It is given that,
[tex](e^{2-\sqrt{3}})^{2+\sqrt{3}}[/tex]
Since
[tex](a^x)^y=a^{xy}[/tex]
That implies,
[tex]\begin{gathered} (e^{2-\sqrt{3}})^{2+\sqrt{3}}=e^{(2-\sqrt{3})(2+\sqrt{3})} \\ =e^{4-3} \\ =e^1 \\ =e \end{gathered}[/tex]
Hence, the answer is e.
