Given the following system of linear equation:
2y + 4 = 8x
y = 4x - 4
Let's determine the solution of the two equations by Substitution.
Substitute y = 4x - 4 in 2y + 4 = 8x.
[tex]2y+4=8x[/tex][tex]2(4x-4)+4=8x[/tex][tex]8x-8+4=8x[/tex][tex]8x-4-8x=8x\text{ - 8x}[/tex][tex]\text{ -4 = 0}[/tex]Therefore, the given system of equations has no solution.
